→ Cryoscopic and ebullioscopic constants
A solution contains $2.00\; g $ of a macromolecule in $ 15.0\; g $ of carbon tetrachloride. It boils at $77.85 ^ oC$ What is the molar mass of the macromolecule?
$t$=carbon tetrachloride and $m$= macromolecule $\mu_m$ $=$ $\frac{1000\cdot n}{m_t}$ $=$ $\frac{1000\cdot m_m}{M_m\cdot m_t}$ $\Delta T$ $=$ $K_{eb}\mu_m$ so: $M_m$ $=$ $\frac{K_{eb}\cdot 1000\cdot m_m}{m_t\Delta T}$ $=$ $\frac{1000\cdot 4.95\cdot 2.00}{(77.85-76.50)\cdot 15.0 }$ $\approx$ $489\frac{g}{mol}$
