Assuming complete ionic dissociation of the following salts, calculate the boiling temperature of aqueous solutions of
a) Magnesium chloride $(\mu=0.50)$
b) Iron(III) chloride $(\mu=0.50)$
a) $s$ = magnesium chloride $MgCl_2$
Each mole gives by dissociation 3 moles of ions!
$\Delta T$ $=$ $K_{eb}\cdot 3\cdot \mu_s$
$\Delta T$ $=$ $0.512\cdot 3\cdot 0.50$ $=$ $0.79^oC$
$t_{eb}=100+0.79=100.79^oC$
a) $s$ = iron(III) chloride $FeCl_3$
Each mole gives by dissociation 4 moles of ions!
$\Delta T$ $=$ $K_{eb}\cdot 3\cdot \mu_s$
$\Delta T$ $=$ $0.512\cdot 4\cdot 0.50$ $=$ $1.02^oC$
$t_{eb}=100+1.02=101.02^oC$
