→ Cryoscopic and ebullioscopic constants
A solution contains $7.4\; g $ of a non-volatile and undissociated solute in $250\;g $ water. It boils at $100.26^ oC$ What is the molar mass of the solute?
$w$=water and $s$= solute $\mu_s$ $=$ $\frac{1000\cdot n}{m_w}$ $=$ $\frac{1000\cdot m_s}{M_s\cdot m_w}$ $\Delta T$ $=$ $K_{eb}\mu_s$ so: $M_s$ $=$ $\frac{K_{eb}\cdot 1000\cdot m_s}{m_w\Delta T}$ $=$ $\frac{1000\cdot 0.512\cdot 7.4}{(100.26-100)\cdot 250 }$ $\approx$ $58\frac{g}{mol}$
