The ideal gas law in the kinetic theory of gases

The pressure and the kinetic energy of molecules

The →    study of pressure as part of the kinetic theory gave the following result: $P=\frac{mNu^2}{3V}$ where $P$ is the pressure of the gas $V$ is the volume of the gas $m$ is the mass of one molecule $N$ is the number of molecules Considering that the average kinetic energy of a molecule is $E_{kin}=\frac{1}{2}mu^2$ we have: $P$= $\frac{mNu^2}{3V}$ = $\frac{2N}{3V}\frac{1}{2}mu^2$ = $\frac{2N}{3V}E_{kin}$

Pressure of an ideal gas: $P$ $=$ $\frac{2}{3}\frac{N}{V}E_{kin}$ where $\frac{N}{V} $ is the molecular density (number of molecules per $m^3$) $E_{kin}$ is the average kinetic energy of the molecules ( $J$) The pressure of an ideal gas is proportional to the molecular density and the average kinetic energy of molecules

and so: $P\cdot V $ $=$ $\frac{2}{3}N E_{kin}$ $=$ $\frac{2}{3}N\frac{1}{2}mu^2\,(1)$

The ideal gas law and the temperature

The well-known →    ideal gas law is: $P\cdot V=n\cdot R\cdot T$ where: $n=\frac{N}{6,023\cdot 10^{23}}$ is the quantity (number of moles) $T$ is the absolute (Kelvin) temperature $R= 8.314\frac{J}{K\cdot mol}$ is the real gas constant Let's assume $k$ $=$ $\frac{R}{6,023\cdot 10^{23}}$ $=$ $\frac{8.314}{6,023\cdot 10^{23}}$ $=$ $1,38\cdot 10^{-23}\frac{J}{K\cdot molecule}$ then the ideal gas law gives: $P\cdot V $ $=$ $\frac{N}{6,023\cdot 10^{23}}k\cdot 6,023\cdot 10^{23} T=$ $N\cdot k\cdot T\,(2)$ Comparing (1) and (2) : $E_{kin}=\frac{3}{2}kT$ which gives us (finally) a reasonable interpretation of this quantity we call temperature:

Average kinetic energy of a molecule of an ideal gas: $E_{kin}=\frac{3}{2}kT$ where $k=1,38\cdot 10^{-23}$ is Boltzmann's constant $T$ is the absolute temperature ($K$) The temperature is a measure of the average kinetic energy of the molecules

The mean square speed of the molecules

The previous law also allows calculation of the mean square speed of the molecules in an ideal gas: $E_{kin}=\frac{3}{2}kT$ $\frac{1}{2}mu^2=\frac{3}{2}kT$ $u=\sqrt{\frac{3kT}{m}}$

Mean square speed of a molecule in an ideal gas: $u=\sqrt{\frac{3kT}{m}}$ where $T$ is the Kelvin temperature $k=1.38\cdot 10^{-23}$ is Boltzmann's constant $m$ is the mass of one molecule