Calculate the volume of a $32.14\%$ solution S of hydrochloric acid ($\rho_S$ $=$ $1.16\frac{g}{mL)}$ that can be obtained from $20\;mol$ of hydrochloric gas.
$m_{HCl}$ $=$ $n_{HCl}\cdot M_{HCl}$ $=$ $20\cdot 36.5$ $=$ $730 \;g$ $\%_{HCl}$ $=$ $\frac{m_{HCl}\cdot 100}{m_S}$ $m_S$ $=$ $\frac{m_{HCl}\cdot 100}{\%_{HCl}}$ $=$ $\frac{730\cdot 100}{32.14}$ $=$ $2271 g$ $V_S$ $=$ $\frac{m_S}{\rho_S}$ $=$ $\frac{2271}{1.16}$ $=$ $1.96\cdot 10^3mL$
