Calculate the volume of concentrated sulfuric acid $S$ with density of $1.84$ and containing $98\%$ acid that must be taken to prepare a $1\;L$ $0.5M$ solution s.
$n_{H_2SO_4}$ $=$ $c_{H_2SO_4 \; dans s}\cdot V_{s}$ $=$ $0.5\cdot 1$ $=$ $0.5\; mol$ $m_{H_2SO_4}$ $=$ $n_{H_2SO_4}\cdot M_{H_2SO_4}$ $=$ $0.5\cdot 98$ $=$ $49\;g$ $\%_{H_2SO_4}$ $=$ $\frac{m_{H_2SO_4}\cdot 100}{m_S}$ $m_S$ $=$ $\frac{m_{H_2SO_4}\cdot 100}{\%_{H_2SO_4}}$ $=$ $\frac{49\cdot 100}{98}$ $=$ $50 \;g$ $\rho_S$ $=$ $1.84\frac{g}{mL}$ $V_S$ $=$ $\frac{m_S}{\rho_S}$ $=$ $\frac{50}{1.84}$ $=$ $2.7\cdot 10^1\;mL$
