Concentration of aqueous solutions

Exercise 8

    

Calculate the mass of a $ 38.56\% $ solution S of potash (potassium hydroxide) obtainable from $10.0$ g of this pure substance.

$\%_{KOH}$ $=$ $\frac{m_{KOH}\cdot 100}{m_S}$ $m_S$ $=$ $\frac{m_{KOH}\cdot 100}{\%_{KOH}}$ $=$ $\frac{10.0\cdot 100}{38.56}$ $=$ $2.59\cdot 10^1\; g$