Factorisiere mit der Differenz von Quaraten: a2 - b2 =(a + b)(a - b)

Go !

Factorisiere!

$\LARGE 4x^2-49 =$	$\LARGE (2x+7)(2x-7) $
$\LARGE 16-(x+3)^2 =$	$\LARGE (1-x)(x+7)$
$\LARGE 16-(x+3)^2 =$	$\LARGE (1-x)(x+7)$
$\LARGE 9(x+1)^2-1 =$	$\LARGE (3x+4)(3x+2)$
$\LARGE 9a^4x^6-25b^4y^6 =$	$\LARGE (3a^2x^3+5b^2y^3)(3a^2x^3-5b^2y^3)$
$\LARGE (4x-5)^2-(2x-3)^2 =$	$\LARGE (2x-2)(6x-8)=4(x-1)(3x-4)$