Law of Boyle

Tutorial 2

            

A gas occupies a volume of $ 200\; cm^3 $ at $ 850 \; mmHg $. What will be its pressure (in $ Pa $) if the volume is compressed to $ 0.15 \; L $, the temperature remaining constant ? Solution (Click): Conversion to $cm^3$: ..........$0.15\;L=150\;cm^3$ Law of Boyle : ..........$P_1\cdot V_1=P_2\cdot V_2$ Calculation: ..........$P_1=\frac{P_2\cdot V_2}{V_1}$ = $\frac{850\cdot 200}{150} = 1133\;mmHg$ = $\frac{1133}{760}\;atm$ = $\frac{1133}{760\cdot 1.0133}\;bar$ = $\frac{1133\cdot 10^5}{760\cdot 1.0133}\;Pa$ = $1.477\cdot 10^5\;Pa$