A mass of nitrogen occupies a volume of $ 10\; L $ at $ 740 \; mmHg $.
What will be its volume at $ 1 \; atm $, the temperature remaining constant ?
Solution (Click):
Conversion to $mmHg$: ..........$1\;atm=760\;mmHg$
Law of Boyle : ..........$P_1\cdot V_1=P_2\cdot V_2$
Calculation: ..........$V_1=\frac{P_2\cdot V_2}{P_1}$ = $\frac{740\cdot 10}{760} = 9.74\;L$
