Concentrations: density, relative density, percentage, molarity, mass concentration

Tutorial 8

    

Use the following schematic "lattice" and →    the definitions to resolve the following exercise:

Exercise Calculate the volume of a $32.14\%$ hydrochloric acid solution ($d = 1.16$) that can be made from $ 20.0$ moles of pure acid (hydrochloric gas). Solution (Click): Scheme and Formulas: .......... Calculation: ..........$m_{so}=n_{so}\cdot M{so}$ $=$ $20.0\cdot 36.5=730\;g$
because $M_{so}=M_{HCL}=36.5\frac{g}{mol}$
$m_{S}$ $=$ $\frac{m_{so}\cdot 100}{\%_{so}}$ = $\frac{730\cdot 100}{32.14}$ = $2271 \; g$
$\rho_S$ = $d_S\cdot 1.0\frac{g}{mL}=1.16\frac{g}{mL}$
$V_S=\frac{m_S}{\rho_S}$ =$\frac{2271}{1.16}=1958\;mL$