Alkane structure and analysis
Exercise 4
$1000\; cm^3$ s.t.p. of a linear alkane have a weight of $1,97\; g$ .
Identify this alkane!
Number of moles:
$n=\frac{V}{22,4}=\frac{1}{22,4}\; mol$
Molar mass:
$M=\frac{m}{n}$ $ =$ $\frac{1,97\cdot 22,4}{1}$ $=$ $ 44 \frac{g}{mol}$
Molecular formula: $C_nH_{2n+2}$
$M=12n+2n+2 =44$
so: $n= 3$
Molecular formula: $C_3H_8$
It's propane!
