A non-cyclic alkane contains $83,72\%\; C$ .
1) Find the molecular formula!
2) Knowing that monochlorination leads to three chloroalkanes, find its condensed formula!
Molecular formula: $C_nH_{2n+2}$
$M=12n+2n+2$
$\%C=\frac{12n\cdot 100}{14n+2}=83,72$
so: $n= 6$
Molecular formula: $C_6H_{14}$
Condensed formula: $CH_3C(CH_3)_2CH_2CH_3$
Monochloration on one of 3 similar left primary carbon atoms $CH_3$ or on the secondary carbon $CH_2$ or finally on the primary carbon $CH_3$ on the right side.
