Calculate the pH of a $ 24.53 \frac{g}{L} $ trichloroacetic acid solution at ! Formula of trichloroacetic acid?
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$CCl_3COOH$
Calculate its initial molarity
$c_{CCl_3COOH}=\frac{24.53}{163.5}=0.15\;M$
Equation ?
With $x=[H_3O^+]$: $x^2\;+\;10^{-0.70}\;x\;-\;10^{-0.70}\;0.15\;=\;0$ $x\;=\;0.10 $
pH ?
$pH\;=\;-log\; x\;=\;1.0$
