Calculate the pH of a $ 0.25 M$ acetic acid solution! Formula of acetic acid?
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$CH_3COOH$
Equation ?
With $x=[H_3O^+]$: $x^2\;+\;10^{-4.75}\;x\;-\;10^{-4.75}\;0.25\;=\;0$ $x\;=\;2.11\;10^{-3} $
pH ?
$pH\;=\;-log\; x\;=\;2.67$
