pH of acids, bases and salts
Exercise 2

Calculate the $pH$ of a acide iodhydrique 0.379 $\frac{g}{L}$ solution
Strong acid
Number of moles in $1\;L$:
$n$ $=$ $\frac{m}{M}$
(with $m$ = 0.379$ \;g$
and $M$ = 127.91) =
0.003$\;mol$
$pH$ $=$ $-log\;c$ =
$-log \;$0.003= 2.53