pH of acids, bases and salts
Exercise 2

Calculate the $pH$ of a acide chlorhydrique 0.28 $\frac{g}{L}$ solution
Strong acid
Number of moles in $1\;L$:
$n$ $=$ $\frac{m}{M}$
(with $m$ = 0.28$ \;g$
and $M$ = 36.46) =
0.0077$\;mol$
$pH$ $=$ $-log\;c$ =
$-log \;$0.0077= 2.11