pH of acids, bases and salts

Exercise 2

   

Calculate the $pH$ of a acide chlorhydrique   0.209 $\frac{g}{L}$ solution

Strong acid Number of moles in $1\;L$: $n$ $=$ $\frac{m}{M}$ (with $m$ = 0.209$ \;g$ and $M$ = 36.46) = 0.0057$\;mol$ $pH$ $=$ $-log\;c$ = $-log \;$0.0057= 2.24