pH of acids, bases and salts
Exercise 2

Calculate the $pH$ of a acide chlorhydrique 0.78 $\frac{g}{L}$ solution
Strong acid
Number of moles in $1\;L$:
$n$ $=$ $\frac{m}{M}$
(with $m$ = 0.78$ \;g$
and $M$ = 36.46) =
0.0214$\;mol$
$pH$ $=$ $-log\;c$ =
$-log \;$0.0214= 1.67