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Commutativité: 2·3 =3·2 ; 2+3 =3+2; 2-3 =-3+2 | 
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Got it ! Simplifier: $x(x-1)- (1-x)(-x)$ = $x-(-x)(-1) - 1$ = -$ab(-c)+abc+(-a)b(-c) - bac) $ = $1-\{1-[1+(3-2^0)^2]^1 \}a +1 $ =
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Commutativité: 2·3 =3·2 ; 2+3 =3+2; 2-3 =-3+2 |
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Got it ! Simplifier: $x(x-1)- (1-x)(-x)$ = $x-(-x)(-1) - 1$ = -$ab(-c)+abc+(-a)b(-c) - bac) $ = $1-\{1-[1+(3-2^0)^2]^1 \}a +1 $ =