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Priorities: parentheses, brackets, braces | 
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Got it ! Calculer pour $x = 3$: $2x$ = $x-(x+3)]$ = -$2(1+x)^2 $ = $1-\{4-[1+(5-x^2)]^2 \} $ = Calculate with $x = -2$: $x(x-1)$ = $2x-[1-(x+3)]$ = -$\{2[1+(1+x)^2] \} $ = $1-\{4-[1+(5-x^2)^2]^2 \} $ =
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Priorities: parentheses, brackets, braces |
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Got it ! Calculer pour $x = 3$: $2x$ = $x-(x+3)]$ = -$2(1+x)^2 $ = $1-\{4-[1+(5-x^2)]^2 \} $ = Calculate with $x = -2$: $x(x-1)$ = $2x-[1-(x+3)]$ = -$\{2[1+(1+x)^2] \} $ = $1-\{4-[1+(5-x^2)^2]^2 \} $ =