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Distributivität: 2·(3 ± 4) = 2· 3 ± 2· 4 | 
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Go ! $x(x+1) = xx +1x = x^2 +x $ $-(a-b) = (-1)(a-b) =(-1)a -(-1)b = -a +b$ $(2+a)5 + 5(3-a) = 10+5a+15-5a = 25$ $2(a+2b) $ = $(ab+1)(-3) $ = $x^2(x^3 + 3x) $ = $-(-a+b) $ = $2(ab+1)-(1+2ba) $ =
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Distributivität: 2·(3 ± 4) = 2· 3 ± 2· 4 |
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Go ! $x(x+1) = xx +1x = x^2 +x $ $-(a-b) = (-1)(a-b) =(-1)a -(-1)b = -a +b$ $(2+a)5 + 5(3-a) = 10+5a+15-5a = 25$ $2(a+2b) $ = $(ab+1)(-3) $ = $x^2(x^3 + 3x) $ = $-(-a+b) $ = $2(ab+1)-(1+2ba) $ =