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- ρ S
- Volumenmasse_S
- g/mL
- Volumenmasse_S
-
- → ρ S g/mL = mS g / VS mL
- 2_3
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- d S
- Dichte_S
-
- Dichte_S
-
- m S
- Masse
- g
- Masse
-
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- → mS g = ( mD g · 100 ) / %D
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- V S
- Volumen_S
- mL
- Volumen_S
-
- → VS mL = mS g / ρS g / mL
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- → VS L = nD g / cD mol / L
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- n D
- Mole_D
- mol
- Mole_D
-
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- → nD mol = cD mol/L · VS L
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- → nD mol = bD mol/kg · mV kg
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- → nD mol = nV mol · ( xD / (1-xD))
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- m D
- Masse_D
- g
- Masse_D
-
- → mD g = MD g/mol · nD mol
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- M D
- Molare Masse_D
- g/mol
- Molare Masse_D
-
- → MD g/mol = mD g / nD mol
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- cD
- Molarität
- mol/L
- Molarität
-
- → cD mol/L = nD mol / VS L
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- % D
- Prozentsatz_D
- %
- Prozentsatz_D
-
- → %D = (100 · mD g) / mS g
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- C D
- Konzentration_D
- $g/L$
- Konzentration_D
-
- m V
- Masse_V
- g
- Masse_V
-
- → mV g = MV g/mol · nV mol
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- n V
- Mole_V
- mol
- Mole_V
-
- → nV mol = mV g / MV g/mol
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- → nV mol = nD mol · (1-xD / xD)
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- b D
- Molalität_D
- mol/kg$
- Molalität_D
-
- → bD mol/kg = nD mol / mV kg
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- x D
- Molenbruch_D
- Molenbruch_D
-
- → xD = nD mol / (nD mol + nV mol)
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- M V
- Molare Masse_V
- g/mol
- Molare Masse_V
-
- → MV g/mol = mV g / nV mol
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Lösungen: Alle chemischen Grössen betreffend Lösung und gelöste Substanz: Konzentration, Masse , Volumen
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$S$ = Lösung $D$ = Gelöste Substanz $V$ = Lösungsmittel