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The potential of a → hydrogen electrode with $ p_{H_2} = 1\; atm $ immersed in a solution of hydrochloric acid was worth: $E$= $-0.118\;V$ Calculate the $pH,\; [H^+]$ and concentration expressed in $\frac{g}{L}$ of this solution.
$pH$ $ = $ $-\frac{E}{0.059}$ $ = $ $ 2.0 $
$[H^+]$ $ = $ $10^{-pH}$ $ = $ $ 0.01\frac{mol}{L} $
Since the acid is completely dissociated, the number of moles $ H^+ $ is equal to the number of moles $ HCl $ at the start and we have: $c_{HCl}$ $ = $ $0.01\cdot M_{HCl} $ $ = $ $0.365 \frac{g}{L}$