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Calculate → the equilibrium constant of the reaction between the zinc metal and a solution of silver nitrate at $ 25^oC$ (standard!). $Zn(s)$ -2$e^-+2Ag^+(aq)$ +2$e^-$ $\leftrightarrows 2Ag(s)+Zn^{2+}(aq)$
$E^o$ $ =$ $ E^o_1-E^o_2=1.57\; V$
$log\;K$ = $\frac{n}{0.059}E^o$ = $\frac{2}{0.059}1.57$ = $53$ $K$ = $10^{53}$