1) Prove that 1 mole of any gas has ntp ($ 0\;^oC $ and $ 1\;atm $) a volume of $ 22.4\; L $ 2) Establish ntp: $ \rho_{gas} = \frac{M}{22.4} \; \frac{g}{L} $ 3) Establish ntp: $d_{gas}=\frac{M}{29.0}$ Solution (Click): 1) Ideal gas law for one mole ntp: .......... 2) Taking $n$ moles of gas ntp:.......... 3) Knowing that ntp: $\rho_{air}=1.292\;\frac{g}{L}$, it follows:..........