Concentrations: Dilution and mixture

Tutorial 2

        

Progressive exercise What volume of $2.0 M $ nitric acid (M = molar) must be supplemented by water to make $1.0 \; L $ of a $ 0.10 \; M $ solution ? Calculation: Final solution: First we calculate .......... the number of nitric acid moles:
$n_{so}=0,10\cdot 1,0=0,10\; mol $ Concentrated solution: We now know ..........the number of nitric acid moles: $0,10\; mol$ and its molarity: $2,0 \;M$ Therefore it can be computed ..........the volume:
$V_S=\frac{n_{so}}{[so]}$ = $\frac{0,10}{2,0}=0,05\;L$