The mole

Tutorial 7

    

Calculate the atomic mass of the cadmium, knowing that by decomposition of $ 0.764 \; g $ of $ CdCl_2 $ one gets $ 0.468 \; g $ of pure cadmium $ Cd $ and chlorine. Go through the number of moles of chlorine!

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$m_{Cl}$ $=$ $0.764-0.468$ $=$ $0.296\;g$

Number of moles of chlorine atoms= $\frac{0.296}{35.5}\;mol$

Number of moles of cadmium atoms = $\frac{0.296}{2\cdot 35.5}\;mol$ Each molecule contains two atoms of chlorine and only one of cadmium!

Atomic (molar) mass of $Cd$= $M$ $=$ $\frac{m}{n}$ $=$ $\frac{0.468}{\frac{0.296}{2\cdot 35.5}}$ $ = $ $112\frac{g}{mol}$