$pH$ of weak bases

Tutorial 8

         

Here is a $ 0.050 \; M $ solution of the weak base pyridine $(C_5H_5N$ , $K_b$ $=$ $1.7\cdot 10^{-4})$ $C_5H_5N$ $ +$ $H_2O$ $HC_5H_5N^+$ $+$ $OH^-$

We found: $[OH^-]$ $=$ $x$ $=$ $1,3\cdot 10^{-2} \;M$ How to calculate the $ pH $ of this solution ?

a) find $pH$ $=$ $- log [ H_3O^+ ]$ b) find $pOH$ $=$ $- log[ OH^- ]$, then $pH$ $=$ $14-pOH$ c) find $[ H_3O^+ ]$ $=$ $\frac{K_e}{[ OH^- ]} $ , then $pH$ $=$ $- log [ H_3O^+ ]$ d) find $[ H_3O^+ ]$ $=$ $10^{-pH}$

Methods b) or c) are correct, We finally find: $pH$ $=$ $12.1$