Here is a $ 0.050 \; M $ solution of the weak base pyridine $(C_5H_5N$ , $K_b$ $=$ $1.7\cdot 10^{-4})$
$C_5H_5N$ $ +$ $H_2O$ 
$HC_5H_5N^+$ $+$ $OH^-$
Which side will move the reaction to reach the equilibrium ?
a) to the left b) to the right c) it will not move, since it is already in equilibrium
b) The reaction will move to the right