How does the strong base $ Sr (OH) _2 $ dissociate in water?
a) $Sr(OH)_2$ $+$ $2H_2O$ 
$Sr(OH)_4^-$ $+$ $H_3O^+$
b) $Sr(OH)_2$ $+$ $2 H_3O^+$ $Sr^{2+}$ $+$ $2 H_2O$
c) $Sr(OH)_2$ $Sr^{2+}$ $+$ $2 OH^-$
d) $Sr(OH)_2$ $SrO$ $+$ $H_2O$
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Answer : c) $Sr(OH)_2$ $Sr^{2+}$ $+$ $2 OH^-$