The analysis of $0.59\;g$ of a gaseous organic substance $A$ gave
$1.32\;g\;CO_2$,
$0.81\;gH_2O$ and
$0.17\;g\; NH_3 $
The vapor density (NTP) is $d$ $ =$ $ 2.03$
1) Find the molecular formula!
2) The substance has a strong smell of rotten fish. Which is it?
1)
In $0.59\; g$ :
$m_C=\frac{1.32\cdot 12}{44}\;=\;0.36 \; g$
$m_H=\frac{0.81\cdot 2}{18}\;=\;0.09\; g$
$m_N=\frac{0.17\cdot 14}{17}\;=\;0.14\; g$
There is no other element !
$M_A = d\cdot \; 29 $ (see → here)
= $\approx 59 \frac{g}{mol}$
In one mole. we have:
$59\cdot \frac{0.36}{0.59} \; \cdot \frac{1}{12} \;=\; 3\;mol \; C$
$59\cdot\frac{0.09}{0.59} \; \cdot \frac{1}{1} \; =\; 9\;mol \; H$
$59\cdot \frac{0.14}{0.59} \; \cdot \frac{1}{14}\;=\; 1\;mol \; N$
Molecular formula:
$C_3H_9N$
2)
It is trimethylamine .
