Basic and nucleophilic reactions of amines

Exercise 2

$0.59\;g$ of a saturated aliphatic amine is dissolved in a little water. It is titrated by $1\frac{mol}{L}$ hydrochloric acid solution . The equivalent term is reached when we added $10\;mL$ acid. 1) Calculate the molar mass of the amine 2) Find its molecular formula 3) Write the I.U.P.A.C. names of all possible amines 4) Add the equation (in non-ionic form) resulting from the reaction of one of these amines with $HCl$ and calculate the mass of salt obtained after evaporation of the water at the end of assay.

1) $n_{amine}$ $=$ $n_{acid}$ = $V_{acid}\cdot [acid]$ $=$ $0.010$ $M_{amine}$ $=$ $\frac{m_{amine}}{n_{amine}}$ $=$ $59\; \frac{g}{mol}$ 2) Aliphatic saturated amine : $C_nH_{2n+3}N$ $12n$ $+$ $2n$ $+$ $3$ $+$ $14$ $=$ $59$ $n$ $=$ $3$ Molecular formula: $C_3H_9N$ 3) Propan-1-amine, Propan-2-amine 1-methylethanamine, N-methylethanamine, N,N-dimethylmethanamine 4) $C_3H_9N$ $+$ $HCl$ $\rightarrow$ $C_3H_{10}NCl$ $n_{salt}$ $=$ $n_{amine}$ $m_{salt}$ $=$ $n_{salt}\cdot M_{salt}$ $=$ $0.010\cdot 95.5$ $=$ $0.955\; g$