Acid-base theory

Buffers

Exercise 4

       

Calculate the change in $pH$ achieved by adding $5.0\; mL$ $H Cl$ $0.100\; M$ to

a) $95.00 \; mL$ of a $0.100\; M$ $NH_3$ and $0.100\; M$ $NH_4Cl$ solution

$\Delta pH$ $ = $ $0.046 $

b) $95.00 mL$ water

$\Delta pH$ $ = $ $4.70 $