The bile of a healthy man can have to the extreme $[OH^-]$ $=$ $4.0\cdot 10^{-6}\frac{mol}{L}$. Calculate its pH
$pOH$ $=$ $-log(4.0\cdot 10^{-6})$ $=$ $5.4$ $pH$ $=$ $14-5.4$ $=$ $8.6$
