Calculate the volume of $19.0\%$ $(d$ $=$ $ 1.11)$ solution S of nitric acid which can be prepared from $50.0mL$ of concentrated acid s with density $1.42$ and containing $69.8\%$ pure acid? Calculate the molarity
$m_{s}$ $=$ $1.42\cdot 50.0$ $=$ $71.0\;g$ $m_{HNO_3}$ $=$ $\frac{71.0\cdot 69.8}{100}$ $=$ $49.6\;g$ $m_S$ $=$ $\frac{49.6\cdot 100}{19.0}$ $=$ $261\;g$ $V_S$ $=$ $\frac{261}{1,11}$ $=$ $2.35\cdot 10^2\; mL$ $n_{HNO_3}$ $=$ $\frac{49.6}{63}$ $=$ $0.787\;mol$ $c_{HNO_3\; in \; S}$ $=$ $\frac{0.787}{0.235}$ $=$ $3,34\;M$
