A solution has $[OH^-]$ $=$ $8.5\cdot 10^-5\;M$. Find the $pH$ !
a) $8.50$ b) $4.07$ c) $7.00$ d) $9.93$
The correct answer is: d) $pH$ $=$ $-log(\frac{K_e}{8.5 \cdot 10^{-5}})$ $=$ $9.93$