Chemical equilibrium

Exercise 5

    

At $800^oC$, consider the equilibrium: $CaCO_3(s)$ $CaO(s)$ $+$ $CO_2(g)$, $K_p$ $=$ $0.220 $ atm Calculate $[CO_2]$

$K_p$ $=$ $p_{CO_2}$ $p_{CO_2}$ $=$ $0.220$ atm $p_{CO_2}$ $=$ $[CO_2]\cdot R\cdot T$ $[CO_2]$ $=$ $\frac{p_{CO_2}}{R\cdot T}$ $= \frac{0.220}{0.082\cdot 1073.15}$ $= 2.5\cdot 10^{-3}\frac{mol}{L}$ .. which explains why volcanism liberates $CO_2$ !!