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Oxydation of red phosporus by chlorine

Equilibrate the equation by oxidation numbers (oxidation states o.n.): $..P$ $+$ $..Cl_2$ $\longrightarrow$ $PCl_5 $

$2P$ $+$ $5Cl_2$ $\longrightarrow$ $2PCl_5 $

Write down the oxidation numbers of all atoms concerned?

o.n. ($P$) in $P$ = 0 o.n. ($P$) in $PCl_5$ = 5 o.n. ($Cl$) in $Cl_2$ = 0 o.n. ($Cl$) in $PCl_5$ = -1

How many electrons are exchanged by one phosphorus atom?

5 electrons are lost by each phosphorus atom.

How many electrons are exchanged by one chlorine atom?

1 electron is absorbed by each chlorine atom.

What is the ratio of phosphorus and chlorine?

5 atoms of chlorine to 1 atom of phosphorus.

What is therefore the ratio of molecules of phosphorus pentachloride and molecules of chlorine Cl2?

5 molecules of chlorine (totalising 10 atoms of chlorine) to 2 molecules of phosphorus pentachloride (totalising 2 atoms of phosphorus).

Equation: $2P$ $+$ $5Cl_2$ $\longrightarrow$ $2PCl_5 $.